Path: utzoo!attcan!uunet!lll-winken!lll-lcc!ames!pacbell!pbhyf!kjk
From: kjk@pbhyf.PacBell.COM (Ken Keirnan)
Newsgroups: comp.unix.questions
Subject: Re: "yesterdate" function?
Message-ID: <4479@pbhyf.PacBell.COM>
Date: 4 Jan 89 17:43:11 GMT
References: <19100001@hpficad.HP.COM>
Reply-To: kjk@pbhyf.PacBell.COM (Ken Keirnan)
Organization: Pacific * Bell, San Ramon, CA
Lines: 47

In article <19100001@hpficad.HP.COM> mcr@hpficad.HP.COM (Matt Reprogle) writes:
>
>I need a way to get yesterday's date in YYMMDD format in a Unix script and put
>it in a file.   I don't want to write a C program implementing an entire
>calendar to do it. 
>
>Can anyone help?  
>
>Matt Reprogle
>
>{everywhere}!hplabs!hpfcla!mcr


If you are using System V, this little program will do what you want.  If
you are using BSD (or some other variant :-)) you are on your own.


-------- CUT HERE -------- CUT HERE -------- CUT HERE -------- CUT HERE 
/*
 * Print yesterdays date in format YYMMDD
 */

#include <time.h>

#define ONEDAY	86400L	/* seconds in a day */

main()
{
	register struct tm *tp;
	long t, time();

	t = time((long *)0) - ONEDAY;
	tp = localtime(&t);

	printf("%.2d%.2d%.2d\n", tp->tm_year, tp->tm_mon+1, tp->tm_mday);
	return(0);
}

-------- CUT HERE -------- CUT HERE -------- CUT HERE -------- CUT HERE 

Ken Keirnan


-- 

Ken Keirnan - Pacific Bell - {att,bellcore,sun,ames,pyramid}!pacbell!pbhyf!kjk
  San Ramon, California	                    kjk@pbhyf.PacBell.COM