Path: utzoo!utgpu!watmath!clyde!att!osu-cis!killer!ames!xanth!mcnc!rutgers!rochester!pt.cs.cmu.edu!b.gp.cs.cmu.edu!Ralf.Brown@B.GP.CS.CMU.EDU
From: Ralf.Brown@B.GP.CS.CMU.EDU
Newsgroups: comp.sys.ibm.pc
Subject: Re: Finding free space on a joined drive
Message-ID: <23ca0289@ralf>
Date: 10 Jan 89 13:18:01 GMT
Sender: ralf@b.gp.cs.cmu.edu
Lines: 28
In-Reply-To: <812@ttrde.UUCP>

In article <812@ttrde.UUCP>, pfales@ttrde.UUCP (Peter Fales) writes:
}/* Use the undocumented DOS function 0x60 to map a relative path to a fully
}qualified path name.  Then use the first character of that pathname to
}determine the drive to which that path belongs.  The key thing here is
}that it works even if the path is on another drive that has been JOINed */

I also tried it on a SUBSTed path, and that worked the same way.  Just a drive
letter did strange things, though (looks like the DOS function doesn't put
anything into the result buffer).


INT 21 - DOS 3+ internal - RESOLVE PATH STRING TO FULLY QUALIFIED PATH STRING
        AH = 60h
        DS:SI -> ASCIZ relative path string
        ES:DI -> 67???-byte buffer for ASCIZ fully qualified name
Return: buffer filled with qualified name of form D:\PATH
        may return error code, unknown.
Note:   if path string is on a JOINed drive, the returned name is the one that
        would be needed if the drive were not JOINed; similarly for a SUBSTed
        drive letter.  Because of this, it is possible to get a qualified name
        that is not legal with the current combination of SUBSTs and JOINs


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