Xref: utzoo sci.astro:3339 sci.space:9238 Path: utzoo!attcan!uunet!lll-winken!ncis.llnl.gov!helios.ee.lbl.gov!nosc!ucsd!rutgers!mailrus!purdue!bu-cs!dartvax!eleazar.dartmouth.edu!dalex From: dalex@eleazar.dartmouth.edu (Dave Alexander) Newsgroups: sci.astro,sci.space Subject: Re: Finding Lagrange's Libration Points Message-ID: <11910@dartvax.Dartmouth.EDU> Date: 22 Jan 89 01:00:47 GMT References: <1989Jan18.044744.18328@sq.uucp> <11854@dartvax.Dartmouth.EDU> <1989Jan20.180839.7800@utzoo.uucp> Sender: news@dartvax.Dartmouth.EDU Reply-To: dalex@eleazar.dartmouth.edu (Dave Alexander) Organization: Dartmouth College, Hanover, NH Lines: 29 In article <1989Jan20.180839.7800@utzoo.uucp> henry@utzoo.uucp (Henry Spencer) writes: > In article <11854@dartvax.Dartmouth.EDU> dalex@eleazar.dartmouth.edu (Dave Alexander) writes: >> In article <1989Jan18.044744.18328@sq.uucp> msb@sq.com (Mark Brader) writes: >>> The L in each of these positions stands for libration, as a body >>> near those positions may librate or oscillate around them, and not >>> for Lagrange. >> So if L1, L2, and L3 are loci of unstable equilibrium, how can we >> expect an object to librate or oscillate about any of them? > You can't, and it won't, without help. An object *precisely* at one > of those points, with *no* perturbations, would stay there, but in the > real world, that doesn't work. I understand that. The question that I was *really* asking was "How can you say that the `L' in L1-5 stands for `libration,' when 60% of such points do not exhibit that behavior?" In light of that, I question Mr. Brader's assertion that the `L' stands for `libration' and not `Lagrange.' -- Dave Alexander -- "Experience has proved that some people indeed know everything." -- Russell Baker