Path: utzoo!attcan!uunet!lll-winken!ames!mailrus!sharkey!mcf!elsie!ado
From: ado@elsie.UUCP (Arthur David Olson)
Newsgroups: comp.windows.x
Subject: Question on shell widgets and geometry
Message-ID: <9079@elsie.UUCP>
Date: 25 Feb 89 19:39:50 GMT
Organization: NIH-LEC, Bethesda, MD
Lines: 39

Suppose I compile this code, naming the executable "try":

	#include <stdio.h>
	#include <X11/Intrinsic.h>
	#include <X11/Box.h>

	int
	main(argc, argv)
	int	argc;
	char *	argv[];
	{
		Widget	widget;
		Arg	args[2];

		widget = XtInitialize("main", "Demo",
			(XrmOptionDescRec *) NULL, 0, &argc, argv);
		XtSetArg(args[0], "width", 100);
		XtSetArg(args[1], "height", 100);
		XtSetValues(widget, args, 2);
		if (argc > 1)
			(void) XtCreateManagedWidget("box", boxWidgetClass,
				widget, (ArgList) NULL, 0);
		XtRealizeWidget(widget);
		XtMainLoop();
	}

If I then use the command
	try -geometry +0+0 x
the geometry option is heeded and the created window appears in the
upper-left-hand corner of my screen.  But if I do a plain
	try -geometry +0+0
(so that the top-level widget has no children) the geometry option is not
heeded.

Should I be surprised by this?  In those cases where I'm using the toolkit
only to get standardized option processing, is there some way of getting
geometry options heeded other than by creating a phony child widget?
-- 
	Arthur David Olson    ado@ncifcrf.gov    ADO is a trademark of Ampex.