Path: utzoo!attcan!uunet!ncrlnk!ncrcae!hubcap!gatech!rutgers!tut.cis.ohio-state.edu!ucbvax!agate!saturn!kjell
From: kjell@saturn.ucsc.edu (Kjell Post)
Newsgroups: comp.lang.c
Subject: Re: programming puzzle (silly)
Message-ID: <6644@saturn.ucsc.edu>
Date: 10 Mar 89 13:38:39 GMT
References: <28336@ucbvax.BERKELEY.EDU>
Reply-To: kjell@saturn.ucsc.edu (Kjell Post)
Organization: University of California, Santa Cruz
Lines: 27

In article <28336@ucbvax.BERKELEY.EDU> klier@ucbarpa.Berkeley.EDU (Pete Klier) writes:
>
>***********************
>main(m,n){scanf("%d",&n);for(m=n>0^n>9;n&&m*=n--;);
>printf(m?"Answer=%d\n":"error\n",m);}
>***********************
>

But you changed the output.
I also get an error compiling this on an ISI68K.

As someone pointed out, my earlier solution breaks when arguments
are supplied at the command line.  I therefore propose the following
as the shortest version:

main(n,m){for(n=scanf("%d\n",&m);m>1&m<10;n*=m--);
printf(m-1?"error\n":"answer is %d\n",n);}

When written on a single line it should count to 91 characters.
I would also like to add the rule that the program should compile
without warnings from cc and lint (except for "scanf returns value
which is always ignored" which is always ignored).
-- 
      For athletes and programmers,  ! Kjell E. Post
a woman is the end of their career.  ! CIS/CE
                                     ! University of California, Santa Cruz
              -- A.Wickberg          ! Email: kjell@saturn.ucsc.edu