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From: maart@cs.vu.nl (Maarten Litmaath)
Newsgroups: comp.unix.questions
Subject: [Repost] Re: csh - now how about pseudo-arrays?
Keywords: Bill `Bugs Bunny' Joy
Message-ID: <2232@solo11.cs.vu.nl>
Date: 31 Mar 89 16:37:39 GMT
References: <2134@pikes.Colorado.EDU>
Organization: V.U. Informatica, Amsterdam, the Netherlands
Lines: 39

pklammer@pikes.Colorado.EDU (Peter Klammer) writes:
\...
\#csh
\
\@ n = 0
\@ n += 1; set entry$n = (EXIT EXIT)

	@ n++; set ...

\@ n += 1; set entry$n = (ADDUSER ADD a new user account)
\@ n += 1; set entry$n = (MODUSER MODIFY a user account)
\...

\#This, for specific case 3, works:
\    set command = $entry3[1]
\    set prompt = "${entry3[2-]}"

Huh? I got `Variable syntax.' on the second assignment! Of course the above
SHOULD work.
The `3' ending the name of the variable seems to cause the trouble,
because the following DOES work:

	set prompt = "${argv[2-]}"

A workaround for our problem is:

	set prompt = "$entry3[2-]"	# forget the braces

\#This, for general case i, fails, with message 'Variable Syntax':
\@ i = 1
\while( $i <= $n )
\    set command = ${entry$i[1]}
\    set prompt = "${entry$i[2-]}"

	eval set command = '"$entry'$i'[1]"'
	eval set prompt = '"$entry'$i'[2-]"'
-- 
 Modeless editors and strong typing:   |Maarten Litmaath @ VU Amsterdam:
   both for people with weak memories. |maart@cs.vu.nl, mcvax!botter!maart