Path: utzoo!yunexus!telly!attcan!uunet!tut.cis.ohio-state.edu!MCC.COM!rfg
From: rfg@MCC.COM (Ron Guilmette)
Newsgroups: gnu.gcc.bug
Subject: what does asm volatile do?
Message-ID: <8903222154.AA02377@riunite.aca.mcc.com>
Date: 22 Mar 89 21:54:25 GMT
Article-I.D.: riunite.8903222154.AA02377
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In the gcc manual (1.34, section 5.16), where the "asm volatile"
construct is described, it says that:

	"If there are no output operands, the instruction will
	not be deleted or moved".

This statement leaves one with the impression that, even when
"volatile" is used in an asm statement, the instruction(s) *may*
be moved if they *do* have output operands.

Is this true?  It seems not.

If not, then perhaps the wording of (5.16) could be improved a bit.

// rfg