Path: utzoo!utgpu!jarvis.csri.toronto.edu!mailrus!ames!amdahl!oliveb!tymix!antares!jms
From: jms@antares.UUCP (Joe Smith)
Newsgroups: comp.sys.amiga
Subject: Re: Struggling through the "C"
Summary: =! is not !=
Message-ID: <433@antares.UUCP>
Date: 2 Apr 89 03:03:15 GMT
References: <12000@louie.udel.EDU>
Reply-To: jms@antares.UUCP (Joe Smith)
Organization: Tymnet QSATS, San Jose CA
Lines: 25

I have seen 2 follow ups to this question, neither of which addresses the
real problem.

In article <12000@louie.udel.EDU> LIZAK98%SNYBUFVA.BITNET@cornellc.cit.cornell.edu (A SHOW OF HANDS) writes:
>
>for(i=0;a[i]=!'\0';i++)
>  printf("%c",a[i]);

The above piece of code will set every character in the string "a" to
a Control-A (ASCII code 001) and will continue past the end of the sting
and wipe out your program.
  '\0' is zero
  !0 is one
  a[i] = !0 sets a[i] to one

Note that the bad code has =! instead of !=.  The correct code is
	for(i=0;a[i]!='\0';i++) {
	   a bunch of "if" statements that handle special characters
	   else printf("%c",a[i]);
	}
-- 
Joe Smith (408)922-6220 | jms@antares.Tymnet.COM or jms@opus.Tymnet.COM
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