Path: utzoo!utgpu!jarvis.csri.toronto.edu!mailrus!ulowell!cbmvax!jesup
From: jesup@cbmvax.UUCP (Randell Jesup)
Newsgroups: comp.sys.amiga.tech
Subject: Re: Audio questions
Message-ID: <6502@cbmvax.UUCP>
Date: 5 Apr 89 04:41:53 GMT
References: <2093@pur-phy> <2097@pur-phy>
Reply-To: jesup@cbmvax.UUCP (Randell Jesup)
Organization: Commodore Technology, West Chester, PA
Lines: 14

In article <2097@pur-phy> murphy@newton.physics.purdue.edu.UUCP (William J. Murphy) writes:
>In article <2093@pur-phy> murphy@newton.physics.purdue.edu (William J. Murphy) writes:
>>My guess is that it will be freq = sampling rate/(428 * 16), but what's the
>>sampling rate?
>Well, to answer my own questions, I dug through an RKM at the bookstore and 
>found that each tic of period = 279.365 ns. Thus the formula is
>
>      frequency = 1/(279.365e-9 * Period * Repeat_of_Data)
>                = 1/(279.365e-9 * 428 * 16)    = 522.7 Hz

	Note: only for NTSC!!!

-- 
Randell Jesup, Commodore Engineering {uunet|rutgers|allegra}!cbmvax!jesup