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From: ark@alice.UUCP (Andrew Koenig)
Newsgroups: comp.lang.c
Subject: Re: Pointers, Structs, and Arrays
Message-ID: <9332@alice.UUCP>
Date: 9 May 89 17:18:09 GMT
References: <743@mccc.UUCP>
Distribution: usa
Organization: AT&T Bell Laboratories, Liberty Corner NJ
Lines: 20

In article <743@mccc.UUCP>, pjh@mccc.UUCP (Pete Holsberg) writes:

> 		*list[i].bar = '\0';

> 
> Now I know that the last line points to the first character in the bar array
> In each struct variable, but how?  If bar = &bar[0], how so the '*' and the
> '&' "get together" to make the last line equivalent to
> 		list[i].bar[0]

Easy ... `.' binds more tightly than any unary operator, so

		*list[i].bar

is equivalent to

		*(list[i].bar)
-- 
				--Andrew Koenig
				  ark@europa.att.com