Path: utzoo!utgpu!jarvis.csri.toronto.edu!mailrus!iuvax!rutgers!cs.utexas.edu!uunet!sdrc!scjones
From: scjones@sdrc.UUCP (Larry Jones)
Newsgroups: comp.lang.c
Subject: Re: Pointers, Structs, and Arrays
Message-ID: <722@sdrc.UUCP>
Date: 10 May 89 21:42:26 GMT
References: <743@mccc.UUCP>
Distribution: usa
Organization: Structural Dynamics Research Corp., Cincinnati
Lines: 28

In article <743@mccc.UUCP>, pjh@mccc.UUCP (Pete Holsberg) writes:
> struct foo
> {
> 	char bar[20];
> } list[100];
> 
> 		*list[i].bar = '\0';
> 
> Now I know that the last line points to the first character in the bar array
> In each struct variable, but how?  If bar = &bar[0], how so the '*' and the
> '&' "get together" to make the last line equivalent to
> 		list[i].bar[0]

Well, the problem is that bar is NOT equivalent to &bar[0].
Rather, list[i].bar is equivalent to &list[i].bar[0], which
should make it easier to see how the "*" and the "&" get
together.

What you have to realize is that bar DOES NOT EXIST -- since it
is a member of a structure, it only exists as part of an actual
instance of the structure and must be referenced as such.
----
Larry Jones                         UUCP: uunet!sdrc!scjones
SDRC                                      scjones@SDRC.UU.NET
2000 Eastman Dr.                    BIX:  ltl
Milford, OH  45150-2789             AT&T: (513) 576-2070
"You can't get a body like mine in a bottle --
unless you push REAL HARD." - Judy Tenuta / Dr. Pepper