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From: jcbst3@cisunx.UUCP (James C. Benz)
Newsgroups: comp.lang.c
Subject: Re: Strange C Problem
Keywords: Linked Lists
Message-ID: <18006@cisunx.UUCP>
Date: 11 May 89 14:40:46 GMT
References: <13812@paris.ics.uci.edu>
Reply-To: jcbst3@unix.cis.pittsburgh.edu (James C. Benz)
Distribution: na
Organization: Univ. of Pittsburgh, Comp & Info Sys
Lines: 46

In article <13812@paris.ics.uci.edu> bvickers@bonnie.ics.uci.edu (Brett J. Vickers) writes:
>  current = first_msg;
>  while (current != NULL) {
>    printf("%s\n",current->string);
>    printf("&");
>    temp = current;
>    current = current -> next;
>    free (temp);
>  }
>  first_msg = NULL;
>  last_msg  = NULL;
>}
>After the function has output its last message, it fails to continue
>on to the next line (printf("&")).  The ampersand isn't output until
>the next call to output_msgs().  

In case nobody has answered this yet, (unlikely, but I'm gonna do it anyway)

First, your line that prints the string has a \n in it.  It is followed by 
a printf that prints a single (special!) character WITHOUT a newline.  The
way your loop is set up, this second printf executes after EACH string from
the linked list is output, not after the whole list.  Further, since no
newline is output following the printf("&") the output buffer is not flushed
(stdout is only flushed on receipt of a newline.  Stderr is flushed on each
character)  So when the last printf("&") is executed, it waits in the stdout
buffer until the next call to printf("%s\n",.....), which is only when you
call output_msg again.  Try putting a printf("\n") OUTSIDE the loop before
exiting the function.  Or look up fflush in the manual.

Newsgroups: comp.lang.c
Subject: Re: mutual reference in structures
Summary: 
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References: <6712@medusa.cs.purdue.edu> <539@lakart.UUCP>
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Reply-To: jcbst3@unix.cis.pittsburgh.edu (James C. Benz)
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-- 
Jim Benz 		     jcbst3@unix.cis.pittsburgh.edu     If a modem 
University of Pittsburgh					 answers,
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