Path: utzoo!attcan!uunet!cs.utexas.edu!sun-barr!apple!bloom-beacon!RIACS.EDU!davy
From: davy@RIACS.EDU
Newsgroups: comp.windows.x
Subject: stupid xpr question
Message-ID: <8905172052.AA10393@intrepid.riacs.edu>
Date: 17 May 89 20:52:53 GMT
Sender: daemon@bloom-beacon.MIT.EDU
Organization: The Internet
Lines: 27


According to the documentation for "xpr", I can use the "-height" and
"-width" arguments to set the height and width of a picture.

I have a dump of a root window ("xwd -root > file").  When I printed it
out with

		xpr -device ps file | lpr

I got a 6x7.5 inch picture.  I want a picture which is 5.2x6.5 inches
(same aspect ratio, but small enough to fit on a page in portrait mode
with 1-inch margins).  So I said...

		xpr -device ps -height 5.2 -width 6.5 file | lpr

And I got a picture which is 3x3.5 inches!  Not exactly what I asked for.

I thought maybe the problem was that I was confusing "height" and
"width" and something weird was happening when "xpr" tried to preserve
the aspect ratio, but when I reversed the numbers above, the same
thing happened.

What am I doing wrong?  Can I get a picture that's 6.5 inches wide by
whatever high?

Just call me confused,
--Dave Curry