Path: utzoo!utgpu!jarvis.csri.toronto.edu!rutgers!mit-eddie!mizar.docs.uu.se!perm
From: perm@mizar.docs.uu.se (Per Mildner)
Newsgroups: comp.lang.c++
Subject: overloading operator->
Message-ID: <8906011506.AA06488@mizar.DoCS.UU.SE>
Date: 1 Jun 89 15:17:10 GMT
Sender: daemon@eddie.MIT.EDU
Lines: 39


Jonathan Shopiro and Jerry Schwarz of AT&T both supplied the correct
code to do what I wan't. operator-> should be declared to return a
pointer. I still don't understand why g++ refuses to inline code it.

class Object {
public:
  int a;
};

class Pointer {
  int data;
public:
  Object* p;
  Object* operator ->();
  Object& operator *();
};

inline Object* Pointer::operator ->() { // won't inline
  return p;
};

inline Object& Pointer::operator *() { // inline ok
  return *p;
};

int main (int argc, char* argv[]) {
  Object O;
  Pointer P;
  P.p = &O;
  (*P).a = 20; // why does this inline
  P->a = 10;   // and not this?
  return P->a;
};

/* [g++-1.35.1-]
mizar 3% g++ -Wall -O -g operator-test.cc
operator-test.cc:18: warning: inline declaration ignored for function with `...'
*/