Path: utzoo!utgpu!jarvis.csri.toronto.edu!mailrus!tut.cis.ohio-state.edu!bloom-beacon!bu-cs!bucsb!castong
From: castong@bucsb.UUCP (Paul Castonguay)
Newsgroups: comp.lang.c
Subject: Re: Another silly question
Message-ID: <2555@bucsb.UUCP>
Date: 24 May 89 01:15:20 GMT
References: <17812@cup.portal.com> <2336@Portia.Stanford.EDU> <9372@alice.UUCP>
Reply-To: castong@bucsb.bu.edu (paul castonguay)
Followup-To: comp.lang.c
Organization: Boston Univ Comp. Sci.
Lines: 29

>
>> 	The statement that *(a+i) == *(i+a) is therefore invalid.
>
>No, the statment is true.
>-- 

#include<stdio.h>
main()
{
    int *a;
    int i=1;

    a = (int *)malloc(16);
    *a = 0;
    *(a+1) = 4;
    *(a+2) = 0;
    *(a+3) = 0;

    printf("*(a+i) = %d  ", *(a+i));
    printf("*(i+a) = %d\n", *(i+a));
}


Output produced:

*(a+i) = 4  *(i+a) = 4


Does that not show that *(a+i) == *(i+a) ?