Path: utzoo!attcan!uunet!cs.utexas.edu!rutgers!cmcl2!adm!smoke!gwyn
From: gwyn@smoke.BRL.MIL (Doug Gwyn)
Newsgroups: comp.lang.c
Subject: Re: Problem with ()?():() as ending test in for-loop
Message-ID: <10328@smoke.BRL.MIL>
Date: 26 May 89 17:19:00 GMT
References: <17722@mimsy.UUCP> <344.nlhp3@oracle.nl> <17757@mimsy.UUCP>
Reply-To: gwyn@brl.arpa (Doug Gwyn)
Organization: Ballistic Research Lab (BRL), APG, MD.
Lines: 10

In article <17757@mimsy.UUCP> chris@mimsy.UUCP (Chris Torek) writes:
>But e1?e2:e3 *can* be turned into (e1&&e2 || !e1&&e3)

Not always; that may evaluate e1 more than once, which matters if e1
has side effects.

Also, the value of e1?e2:e3 is an appropriately promoted value of e2
or e3, whereas the value of (e1&&e2||!e1&&e3) is either 0 or 1.

Just a warning against taking this discussion too literally..