Xref: utzoo comp.lang.c:18927 comp.sources.wanted:7533
Path: utzoo!utgpu!jarvis.csri.toronto.edu!mailrus!husc6!rutgers!att!occrsh!rjd
From: rjd@occrsh.ATT.COM (Randy_Davis)
Newsgroups: comp.lang.c,comp.sources.wanted
Subject: Re: Day of week routine
Summary: Not C, but shell, and still useful...
Keywords: Does anybody have this?
Message-ID: <716@occrsh.ATT.COM>
Date: 24 May 89 14:46:49 GMT
References: <234@zeek.UUCP>
Reply-To: rjd@occrsh.UUCP (Randy_Davis)
Followup-To: comp.lang.c
Distribution: usa
Organization: AT&T Network & Data Systems, OKC
Lines: 44

In article <234@zeek.UUCP> larry@zeek.UUCP (Larry Podmolik) writes:
|I need a C function that, given a date, would return what day of the
|week it fell on.  Of course, I didn't think to save it at the time.

  Well, this is not C, but it is a cheap and easy shell script that will
do the same, based on the "cal" command.

Randy Davis					UUCP: ...(att!)ocrjd!randy
						      ...(att!)occrsh!rjd
--------------------------cut here--------------------------------------
# How this for simple - "dow", a simple day of week calculator, written 1/11/89
# by Randy Davis.  Error checking and error messages added 3/9/89.

USAGE="Usage: $0 month[1-12] day[1-31] year[00-99] - to calculate the day\nof week for a certain date."

MONTH=$1
DAY=$2
YR=$3

case "$DAY" in
	[1-9]|[12][0-9]|3[01]) ;;
	*) echo $USAGE ; exit ;;
esac
case "$MONTH" in
	[1-9]|1[012]) ;;
	*) echo $USAGE ; exit ;;
esac
case "$YR" in
	[0-9][0-9]) ;;
	*) echo $USAGE ; exit ;;
esac

set `cal $MONTH 19$YR | egrep "^$DAY | $DAY | $DAY$"`

for DOW in Sunday Monday Tuesday Wednesday Thursday Friday Saturday
do
  if [ "$1" = "$DAY" ]
  then
    break
  fi
  shift
done

echo $DOW