Path: utzoo!utgpu!jarvis.csri.toronto.edu!rutgers!att!ulysses!andante!alice!ark
From: ark@alice.UUCP (Andrew Koenig)
Newsgroups: comp.lang.c++
Subject: Re: assignment to `this' is deprecated in C++ 2.0
Message-ID: <9448@alice.UUCP>
Date: 8 Jun 89 00:55:20 GMT
References: <9432@alice.UUCP> <6355@columbia.edu>
Organization: AT&T Bell Laboratories, Liberty Corner NJ
Lines: 30

In article <6355@columbia.edu>, kearns@read.columbia.edu (Steve Kearns) writes:

> What will happen with declaration of a "stack" variable:

> {
>     TypeT T;
>     ...
> }

> Does new() get called with some indication that allocation on
> the stack is expected?  Is new() not called?

operator new is not called; only the constructor is.

> I assume that when a vector is newed():
> {
>     TypeT * tp = new TypeT[100]
>     ...
> }

> then new gets passed 100*sizeof(TypeT)?  

Nope -- again, operator new is not called.

Array types are effectively built-in types for the purpose of
memory allocation, so all requests for array allocation and
deallocation go through the built-in allocator.
-- 
				--Andrew Koenig
				  ark@europa.att.com