Path: utzoo!utgpu!jarvis.csri.toronto.edu!rutgers!att!chinet!les
From: les@chinet.chi.il.us (Leslie Mikesell)
Newsgroups: comp.lang.c
Subject: Re: C problems
Message-ID: <8639@chinet.chi.il.us>
Date: 5 Jun 89 22:38:55 GMT
References: <29@<May> <236100015@mirror> <13566@haddock.ima.isc.com>
Reply-To: les@chinet.chi.il.us (Leslie Mikesell)
Organization: Chinet - Public Access Unix
Lines: 20

In article <13566@haddock.ima.isc.com> karl@haddock.ima.isc.com (Karl Heuer) writes:
>>char **argv;      /* since you are learning it may be easier to understand
>>                     this syntax better by defining it as:  char *argv[]  */

>On the other hand, since this use of [] is a special case which exists nowhere
>else in the language (it works *only* for formal arguments), it may be less
>confusing to stick with "char **argv" after all.

Umm, isn't that the same as:

char *list[] = {
                "one",
                "two",
                "three",
                 0 };

which seems to work as a global definition.  Argv is something similar
so the char *argv[]; declaration makes sense.

Les Mikesell