Xref: utzoo sci.electronics:6414 sci.physics:8407 Path: utzoo!utgpu!jarvis.csri.toronto.edu!rutgers!tut.cis.ohio-state.edu!ucbvax!agate!shelby!labrea!siegman@sierra.Stanford.EDU From: siegman@sierra.Stanford.EDU (Anthony E. Siegman) Newsgroups: sci.electronics,sci.physics Subject: Re: Re^2: HV Cap Fun! Message-ID: <148@sierra.stanford.edu> Date: 2 Jun 89 22:41:47 GMT References: <4924@m2c.M2C.ORG> <3806@mit-amt> <20772@quacky.mips.COM> <166@mother.dde.uucp> <147@sierra.stanford.edu> <2329@quanta.eng.ohio-state.edu> Sender: siegman@sierra.STANFORD.EDU (Anthony E. Siegman) Reply-To: siegman@sierra.UUCP (Anthony E. Siegman) Organization: Stanford University Lines: 10 There's a mechanical analog to the switched-capacitor "where did half the energy go" problem. A slow conveyor belt rolls past a loading chute which dumps dirt or coal or something on the belt at a fixed rate dm/dt (m=mass of dirt dumped). The dirt is instantaneously accelerated to the belt's steady velocity v as it hits the belt's surface. Force required to keep pulling the belt (no friction) = f = dp/dt where dp = dm v = momentum added to the mass dm. Work done in time dt = f dx = dm v^^2 (using dx = v dt). But kinetic energy added to (or carried by) the dirt is only (1/2) dm v^^2. Where's the other half?