Path: utzoo!utgpu!jarvis.csri.toronto.edu!rutgers!tut.cis.ohio-state.edu!ucbvax!hplabs!hp-pcd!hplsla!tomb
From: tomb@hplsla.HP.COM (Tom Bruhns)
Newsgroups: sci.electronics
Subject: Re: Re^2: HV Cap Fun!
Message-ID: <5170038@hplsla.HP.COM>
Date: 2 Jun 89 15:43:37 GMT
References: <166@mother.dde.uucp>
Organization: HP Lake Stevens, WA
Lines: 34

mbe@dde.uucp (Martin Berg) writes:
> ...
>
>If you use an inductor when connecting the capacitors then you 
>would not loose energy (ok, ok a little if the components is not ideal).
>
>But then the resulting voltage would not be 5 V - it would be 7.07 V 
>(for energy preservation).

Bull.  At least it would be only as it passed through.  In a non-
radiating, non-dissipative ("ideal" :-) system, there would be an
oscillatory current that would yield (assuming the junction between
the caps to be the reference terminal and the inductance all lumped
between the other ends of the caps) two sine waves, 180 degrees out
of phase, each going between 0 volts and 10 volts, as measured at
each capacitor.

Repeating a question I posted earlier:  can you think of a _simple_
circuit that will let you get 7.07 volts on each cap, with no
external energy source?  (7.07 volts final value, after an "energy
transfer" period.)  Or here's an easier one:  move all the charge from
one of the capacitors to the other one, so the first cap (orig. 10 V)
is now zero and the second (orig. zero) is 10 V.  Again, no external
energy sources.  You might have to use "ideal" components to do it;
also tell me what sort of loss you would expect in the real world.

>
>By the way: I'm not so sure that the resulting voltage would be 5 V
>in your example.
>-- 
>mbe@dde.dk                        |  "The answer is 42"
>or                                |  D. Adams
>..uunet!mcvax!enea!dkuug!dde!mbe  |
>----------