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From: kenny@m.cs.uiuc.edu
Newsgroups: comp.lang.c++
Subject: Re: Question Re. cout (Simple)
Message-ID: <4800080@m.cs.uiuc.edu>
Date: 10 Jan 90 17:29:27 GMT
References: <7567@hubcap.clemson.edu>
Lines: 25
Nf-ID: #R:hubcap.clemson.edu:7567:m.cs.uiuc.edu:4800080:000:564
Nf-From: m.cs.uiuc.edu!kenny    Jan  9 17:54:00 1990


#include <stdio.h>
#include <stream.h>

main()

{
int* x = new int;

*x = 10;
cout << "1. x = " << *x << '\n';
cout << "\n";
cout << "2. x = " << *x << "\n";
printf("3. x = %d %c",*x,'\n');
}

Question: Why does the first cout (cout << "1. x = " << *x << '\n';)
	  produce the output x = 1010 ??

The '\n', in single quotes, is promoted to an integer before being
passed to cout; the ASCII character value for newline is decimal 10.
This anomaly was an unavoidable misfeature of the original C++
calculus of types; it's fixed in cfront 2.0, gcc, and zortech.

A-T