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From: jeffa@hpmwtd.HP.COM (Jeff Aguilera)
Newsgroups: comp.lang.c++
Subject: Re: Question Re. cout (Simple)
Message-ID: <1520014@hpmwjaa.HP.COM>
Date: 10 Jan 90 22:44:50 GMT
References: <7567@hubcap.clemson.edu>
Organization: HP Microwave Tech. - Santa Rosa, Ca.
Lines: 44

> I am a new C++ user and curious as to why the following program  behaves
> as it does.
> 
> The program:
> -------------------------------------------------------------------------
> #include <stdio.h>
> #include <stream.h>
> 
> main()
> 
> {
> int* x = new int;
> 
> *x = 10;
> cout << "1. x = " << *x << '\n';
> cout << "\n";
> cout << "2. x = " << *x << "\n";
> printf("3. x = %d %c",*x,'\n');
> }
> ------------------------------------------------------------------------
> 
> 
> 1. x = 1010
> 2. x = 10
> 3. x = 10 
> ------------------------------------------------------------------------
> 
> Question: Why does the first cout (cout << "1. x = " << *x << '\n';)
>     produce the output x = 1010 ??
> 
> Bala

Because you are using C++ 1.2, which defines character constants as type
int.  That is, cout << '\n' calls

    ostream& operator<<(ostream&, int)
not
    ostream& operator<<(ostream&, char*)

With 2.0, character constants have type char, resulting in the expected
behavior.

-----
jeffa