Path: utzoo!utgpu!jarvis.csri.toronto.edu!mailrus!uwm.edu!zaphod.mps.ohio-state.edu!usc!henry.jpl.nasa.gov!elroy.jpl.nasa.gov!ames!pacbell!osc!jgk From: jgk@osc.COM (Joe Keane) Newsgroups: sci.electronics Subject: Re: 100V Japanese products on 120V US lines Summary: it's magic Message-ID: <1793@osc.COM> Date: 2 Jan 90 22:25:46 GMT References: <3215@uceng.UC.EDU> <1201@ariel.unm.edu> <25539@cup.portal.com> Reply-To: jgk@osc.COM (Joe Keane) Organization: Object Sciences Corp., Menlo Park, CA Lines: 19 In article <25539@cup.portal.com> dbell@cup.portal.com (David J Bell) writes: >Only a small quibble: the *primary* current is what you have to worry about, >not the secondary: since all the load current flows through both transformer >windings, they get equal current, unlike the usual case where the primary is >low current and the (step-down) secondary is much higher. You'd want to first >find out what the primary current rating *is* before selecting the transformer >to use. To wit: > >Power_rating = sec._voltage (24) * sec._current_rating (e.g. 3A) = 72 Watts >Primary_current_rating = Power_rating / 120VAC, or 0.6 A in this example. This is incorrect. The secondary carries the output current, so, assuming we have a 120VAC to 20VAC transformer, the primary must carry only 1/6 of that current. Also note that only 1/5 of the power consumed by the load actually flows through the transformer, from the secondary to the primary. . . .