Path: utzoo!utgpu!jarvis.csri.toronto.edu!mailrus!umich!samsung!psuvax1!psuvm!auvm!GN!GEOGIOU
From: geogiou@GN.ECN.PURDUE.EDU (Ioannes T Georgiou)
Newsgroups: bit.listserv.hellas
Subject: Re:  Quiz
Message-ID: <9002101402.AA27154@gn.ecn.purdue.edu>
Date: 10 Feb 90 14:02:21 GMT
Sender: The Hellenic Discussion  List <HELLAS@AUVM>
Reply-To: The Hellenic Discussion  List <HELLAS@AUVM>
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1=sqrt(1)*sqrt(1)=sqrt(1)**2=(sqrt(-1)*(-1))**2=(i**2)**2=(-1)**2=1 ===> 1=1

1=sqrt(1) odhgei se paradokso.