Path: utzoo!utgpu!jarvis.csri.toronto.edu!cs.utexas.edu!asuvax!noao!amethyst!raw
From: raw@math.arizona.edu (Rich Walters)
Newsgroups: comp.lang.c
Subject: Re: log10(8)
Message-ID: <1460@amethyst.math.arizona.edu>
Date: 27 Feb 90 02:58:48 GMT
References: <3244@servax0.essex.ac.uk>
Sender: news@amethyst.math.arizona.edu
Organization: Dept. of Math., Univ. of Arizona, Tucson AZ 85721
Lines: 29

In article <3244@servax0.essex.ac.uk> elzea@sersun0.essex.ac.uk (El-Zein A A) writes:
>
>	My calculator gives me 0.9030899 for log(8),
>	While the following code (which I thought would
>	give me the above value of 0.9030899) prints 
>	-312.770165.
>
>	double l;
>	.
>	l = log10(8);
>	printf("%f", l);
>       .
>
>	Can anybody tell me why.
>

Try printf"%lf",l);  after all l is declared to be a double!!!!!!!!



					Richard Walter



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