Path: utzoo!utgpu!jarvis.csri.toronto.edu!cs.utexas.edu!uunet!dino!sharkey!cfctech!ttardis!rlw
From: rlw@ttardis.UUCP (Ron Wilson)
Newsgroups: comp.sys.apple
Subject: Re: Nintendo
Message-ID: <2482@ttardis.UUCP>
Date: 21 Feb 90 02:54:36 GMT
Organization: Gallifrey
Lines: 40

In article <1497@crash.cts.com>, gsnow@pro-freedom.cts.com (Gary Snow) writes:
>In-Reply-To: message from cyliao@eng.umd.edu
>
>In article <1459@crash.cts.com> gsnow@pro-freedom.cts.com (Gary Snow) writes:
>>>In-Reply-To: message from yu-r@yacht.cis.ohio-state.edu
>>>
>>>> Actualy, the 68000 is a 16-bit processor,  and the 68020 and above are
>>>> 32-bit.  the 68000 are found on the Mac+, the oldest mac model available 
>>>> which is a 16-bit machine..
>>>
>>>Well, if you want to get technical, a 68000 is a 16/32 bit CPU.  It has a
>>>16bit data bus, and a 32bit address bus.
>>>
>>>Gary
>
> 	> Uh...excuse me, if you  you say it has  is 16/32 bit CPU thenthe  
>> 6502 or 65c02 should be 8/16 bits because 6502/65c02 has 8 bit data line
>> and 16 bit address bus if I am not wrong. But we dont say it is 8/16 bits
>> processor, do we?
>
>The 6502/65C02 IS an 8/16 bit chip, and I do not know about you, but thats
>what I classify it as.
>
>By the way, I messed up, the 68000 is only a 16/24 bit chip, I was off a bit
>in my calculations (no pun intended).
>
>Gary

Sorry, gentlemen, but your both wrong.

The 68000 is a 16/32 bit cpu because it has a 32 bit arithmatic/logic unit
and 32 bit internal data paths - but only a 16 data bus to the outside
world.

The 65816 and 65802 are 8/16 bit CPUs: 16 bit arithnatic/logic unit and
16 bit internal data paths; with 8 bit data bus to the outside world.

The 65C02 and 6502 are straight 8 bit CPUs.

- Ron Wilson