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From: russotto@eng.umd.edu (Matthew T. Russotto)
Newsgroups: comp.sys.mac
Subject: Re: modem thruput: what do you get?
Message-ID: <1990Feb21.182950.29445@eng.umd.edu>
Date: 21 Feb 90 18:29:50 GMT
References: <7380043@hpwrce.HP.COM>
Sender: news@eng.umd.edu (The News System)
Organization: Maryversity of Uniland, College Park
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In article <7380043@hpwrce.HP.COM> ted@hpwrce.HP.COM ( Ted Johnson) writes:
>How many chars/sec should a "good" implementation of kermit transmit?
>
>Using a Hayes 1200, I got  70 chars/sec
>Using a Hayes 2400, I got 118 chars/sec
>
>A quick back-of-the-envelope calculation shows that the 
>theoritical (sp?) max. thruput is 150 chars/sec and 300 chars/sec,
>for the 1200 and 2400 baud modems (assuming that these both
>use 2 signal levels, so that bps = baud..., which may not be true).
>
Kermit, using small blocks, is pretty slow.  Also, your theroetical max
is off- it's 120cps and 240cps at 8-n-1.  I'm not going to deny that
Red Ryder is a dog though.  If you can use another protocol, do so.
--
Matthew T. Russotto	russotto@eng.umd.edu	russotto@wam.umd.edu
][, ][+, ///, ///+, //e, //c, IIGS, //c+ --- Any questions?