Xref: utzoo rec.ham-radio:18086 sci.electronics:10350 Path: utzoo!utgpu!jarvis.csri.toronto.edu!cs.utexas.edu!rice!uw-beaver!milton!whit From: whit@milton.acs.washington.edu (John Whitmore) Newsgroups: rec.ham-radio,sci.electronics Subject: Re: How does one build LOG AMPS (>60dB dynamic range) Summary: National Semiconductor AN-264 explains it Message-ID: <2154@milton.acs.washington.edu> Date: 27 Feb 90 04:29:42 GMT References: <596@massey.ac.nz> Reply-To: whit@milton.acs.washington.edu (John Whitmore) Organization: University of Washington, Seattle Lines: 37 In article <596@massey.ac.nz> GMoretti@massey.ac.nz (Giovanni Moretti) writes: >I've build a spectrum analyser (0-100MHz) that has a 10.7MHz IF (from >HAM-RADIO years ago) and it works quite well but I'm not happy with the >log-amp/detector. Most log amps use the relationship that the base-emitter voltage of a transistor is proportional to the logarithm of the emitter current (sometimes approximated as the collector current). A good low-noise transistor will follow this "ideal diode" curve for about eight orders of magnitude in the collector current (power ratio 160 dB). Routine use of this effect is complicated by the temperature dependence of the equation, Ie= Is * exp( q* Vbe/( k * T) ) and a good logarithm amplifier either needs a second (matched) transistor at the same temperature to set the operating point, or a thermostat. The National Semiconductor Linear Applications databook has one thermostat-style solution, in AN-264. The thermostat they use employs three transistors, with one transistor doing the logarithm conversion, a second measuring the temperature, and a third acting as the heater. The thermostat approach does NOT require matched transistors. The second approach, with matched transistors is slightly less accurate (mainly because of mismatched emitter resistances at elevated currents), but works at lower total power dissipation. I think the National databook has one of these, also; AN-29, Figure 23. I would suggest using the cookbook circuits, since at the lowest current ranges these are not terribly easy to frequency-compensate (i.e. the op amps will likely oscillate), and these circuits have already been debugged. The second part of your problem is the precise rectification of the IF-frequency signal; all I can think of is a good hot-carrier diode, and keeping 60 dB of accuracy there is not going to be easy. Good luck. Your local National Semiconductor distributor (or the representatives in Australia: telephone (03) 729-6333) can supply the application notes I quoted above. I am known for my brilliance, John Whitmore by those who do not know me well.