Path: utzoo!utgpu!jarvis.csri.toronto.edu!cs.utexas.edu!usc!ucsd!helios.ee.lbl.gov!nosc!crash!pnet01!hawk
From: hawk@pnet01.cts.com (John Anderson)
Newsgroups: comp.sys.amiga.tech
Subject: 32 bit RAM
Message-ID: <1778@crash.cts.com>
Date: 9 Mar 90 02:16:06 GMT
Sender: root@crash.cts.com
Organization: People-Net [pnet01], El Cajon CA
Lines: 19


   Thank you to all those that responded to my inquiries and questions about
32 bit RAM and 16 bit etc.  So basically what I understand to be true is that
32 bit is 4 bytes wide (which I already knew) so it can hold *4* instructions
instead of just *2* like 16 bit RAM? (that is the part I didn't know about). 
I thought each instruction was 32 bits in length and needed to be stored at
two 16 bit addresses so when it was used in 32 bit RAM it took up 32 bits for
that same one instruction.  Am I right so far in saying the first is right and
the second (what I used to think) is wrong?  
   
   
     Also, I got that each instruction is one byte not 4 bytes long but since
the data length is a maximum of 32 bits then this leaves and option to have a
number stored in 32 bits (taking up 4 bytes) if it is needed to be that big(or
that accurate).  Is this also true?  If this is also true then I appreciate
all the help I got from those that replied and helped me.  If only some is tru
then I still thank you and could you shed some light on me on the stuff I
still dont understand?  Even if I'm right could someone in the know let me
know that I got it?  Thanks again...