Path: utzoo!utgpu!jarvis.csri.toronto.edu!cs.utexas.edu!swrinde!zaphod.mps.ohio-state.edu!usc!elroy.jpl.nasa.gov!ames!uhccux!munnari.oz.au!kaukau.comp.vuw.ac.nz!virtue!hamish From: hamish@waikato.ac.nz Newsgroups: comp.sys.amiga.tech Subject: 32-bit Ram & Instruction Lengths. Message-ID: <223.25fd1cf8@waikato.ac.nz> Date: 13 Mar 90 03:16:56 GMT Lines: 26 I quote from the official motorola MC68010/MC68012 16-/32 bit Virtual Memory Microprocessors Advance Information manulal, May 1985. "Instructions are from one to five words in length...." pg 2.4 This means that an instruction is anywhere from 2-10 bytes in length, irrespective of the processor being used, (68008-68030, 020&030 might have longer ones, but I doubt it.) Instructions must start on a word boundary, ie every 16 bits. A 32 bit word is a LONG WORD. pg 1.3 The length of instruction & the instruction itself are specified in the first word of the instruction & the others are the instruction operands. Hope it helps to all involved in possibly misleading statements which have flown past my screen involved in this subject of memory size. Remember 1024k bytes = 512k words = 256k long words. Which also equals 2048 nibbles. Hamish Marson.